What is the subnet ID of the network 192.168.165.189 /26?

What is the subnet ID of the network 192.168.165.189 /26?

• A. 192.168.165.128
• B. 192.168.165.189
• C. 192.168.165.0
• D. 192.168.165.255

Answer: (A)

To determine the subnet ID for the network 192.168.165.189 with a subnet mask of /26, it's important to understand how subnetting works. A /26 subnet mask indicates that the first 26 bits of the IP address are used for the network part, while the remaining 6 bits are used for host addresses within that subnet. The subnet mask corresponding to /26 is 255.255.255.192. This mask divides the IP address space into segments. With a /26 subnet, there are 64 total IP addresses in that subnet (2^6 = 64), which are divided into a range of usable addresses. To find the subnet ID, you can start at the multiple of 64 that is closest to the IP address in question. The range for the subnet starts at 192.168.165.128 and ends at 192.168.165.191. Thus, the subnet ID for this range is 192.168.165.128, which is the first IP address in this subnet and is reserved to identify the network itself. This is why the correct answer is 192.168.165.128, as it represents the subnet ID for all the addresses that fall within

To determine the subnet ID for the network 192.168.165.189 with a subnet mask of /26, it's important to understand how subnetting works. A /26 subnet mask indicates that the first 26 bits of the IP address are used for the network part, while the remaining 6 bits are used for host addresses within that subnet.

The subnet mask corresponding to /26 is 255.255.255.192. This mask divides the IP address space into segments. With a /26 subnet, there are 64 total IP addresses in that subnet (2^6 = 64), which are divided into a range of usable addresses.

To find the subnet ID, you can start at the multiple of 64 that is closest to the IP address in question. The range for the subnet starts at 192.168.165.128 and ends at 192.168.165.191. Thus, the subnet ID for this range is 192.168.165.128, which is the first IP address in this subnet and is reserved to identify the network itself.

This is why the correct answer is 192.168.165.128, as it represents the subnet ID for all the addresses that fall within